# NCERT Solutions for Class 8 Maths Chapter 14 : Factorisation

Click on Member Login to Enter.
No Username with this Email Id exists!

## Chapter 14 : Factorisation

### 14.1 Introduction

14.1.1 Factors of natural numbers
You will remember what you learnt about factors in Class VI. Let us take a natural number, say 30, and write it as a product of other natural numbers, say Thus, 1, 2, 3, 5, 6, 10, 15 and 30 are the factors of 30. Of these, 2, 3 and 5 are the prime factors of 30 (Why?) A number written as a product of prime factors is said to be in the prime factor form; for example, 30 written as 2 × 3 × 5 is in the prime factor form. The prime factor form of 70 is 2 × 5 × 7. The prime factor form of 90 is 2 × 3 × 3 × 5, and so on. Similarly, we can express algebraic expressions as products of their factors. This is what we shall learn to do in this chapter.
14.1.2 Factors of algebraic expressions
We have seen in Class VII that in algebraic expressions, terms are formed as products of factors. For example, in the algebraic expression 5xy + 3x the term 5xy has been formed by the factors 5, x and y,

### 14.2 What is Factorisation?

When we factorise an algebraic expression, we write it as a product of factors. These factors may be numbers, algebraic variables or algebraic expressions. Expressions like 3xy, 5x2 y , 2x (y + 2), 5 (y + 1) (x + 2) are already in factor form. Their factors can be just read off from them, as we already know. On the other hand consider expressions like 2x + 4, 3x + 3y, x2 + 5x, x2 + 5x + 6. It is not obvious what their factors are. We need to develop systematic methods to factorise these expressions, i.e., to find their factors. This is what we shall do now
14.2.1 Method of common factors We begin with a simple example: Factorise 2x + 4. We shall write each term as a product of irreducible factors;
14.2.3 Factorisation using identities
The following solved examples illustrate how to use these identities for factorisation. What we do is to observe the given expression. If it has a form that fits the right hand side of one of the identities, then the expression corresponding to the left hand side of the identity gives the desired factorisation.

### 14.3 Division of Algebraic Expressions

We have learnt how to add and subtract algebraic expressions. We also know how to multiply two expressions. We have not however, looked at division of one algebraic expression by another. This is what we wish to do in this section.Alternatively, we could divide each term of the trinomial by the monomial using the cancellation method.

### 14.4 Division of Algebraic Expressions Continued (Polynomial ÷ Polynomial)

xpression enclosed in a bracket by a constant (or a variable) outside, each term of the expression has to be multiplied by the constant (or the variable). Coefficient 1 of a term is usually not shown. But while adding like terms, we include it in the sum.

### Smartur

Learning is (Super) rewarding!